A parallel plate capacitor is charged to a potential difference of 50 V. It is then discharged through a resistance for 2s and its potential drops by 10V. Calculate the fraction of energy stored in the capacitance
Text Solution
Verified by ExpertsThe correct answer is:
D
Initial energy stored in the capacitor,
… (i)
After 2 s, when the potential drops by 10 V, the final potential is 40 V.
Final energy stored in the capacitor,
… (ii)
Fraction of energy stored 
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